In the reaction
What is the value of n?
Given:
MnO₄⁻ + 8H⁺ + ne⁻ → Mn²⁺ + 4H₂O
Oxidation States:
Mn in MnO₄⁻ = +7
Mn in Mn²⁺ = +2
Change in O.N.
+7 → +2
Gain = 5e⁻
∴ n = 5
Balanced Half Reaction:
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
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