When sulphur dioxide is passed in an acidified K2Cr2O7 solution, the oxidation state of sulphur is changed from;
Reaction:
K₂Cr₂O₇ + H₂SO₄ + SO₂ → Cr³⁺ + SO₄²⁻
Oxidation States of Sulphur:
In SO₂:
S = +4
In SO₄²⁻:
S = +6
Change:
+4 → +6
∴ Oxidation state of sulphur changes from +4 to +6.
The oxidation number of Sulphur in S₈ and S₂F₂ respectively are
MediumThe oxidation state of Xe in Ba2XeO6 is:
MediumThe oxidation state of two terminal and two middle sulphur atoms in respectively are:
MediumChlorine has +1 oxidation state in;
MediumThe number of moles of KMnO4 that will be needed to react completely with one mole of ferrous oxalat
MediumMatch the half-reactions (in column I) with change in oxidation number (in column II)
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