Cl2 changes to Cl− and ClO− in cold and dil. NaOH. The equivalent weight of Cl2 (molar mass = M) will be:
Reaction:
Cl₂ + 2NaOH → NaCl + NaClO + H₂O
Oxidation States:
Cl₂ : 0
Cl⁻ : -1 (Gain = 1e⁻)
ClO⁻ : +1 (Loss = 1e⁻)
Hence,
1 mol Cl₂ undergoes change of 1 electron.
n-factor = 1
Equivalent Weight
= Molar Mass / n-factor
= M / 1
= M
∴ Equivalent weight of Cl₂ = M
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