Two different wires having lengths L1 and L2 , and respective temperature coefficient of linear expansion α1 and α2 , are joined end-to-end. Then the effective temperature coefficient of linear expansion is:

Answer: . — (L1 + L2)αeff ΔT = L1α1 ΔT + L2α2 ΔT (L1 + L2)αeff = L1α1 + L2α2 αeff =

Two different wires having lengths L1 and L2 , and respectiv... — Physics | Mockzy

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Two different wires having lengths L₁ and L₂ , and respective temperature coefficient of linear expansion α₁and α₂ , are joined end-to-end. Then the effective temperature coefficient of linear expansion is:

$\frac{α _{1} L _{1} + α _{2} L _{2}}{L _{1} + L _{2}}$ .

2 $α_{1} α_{2}$

4 $\frac{α _{1} α _{2}}{α _{1} + α _{2}} \frac{L _{1} L _{2}}{( L _{1} + L _{2} ) ^{2}}$

$\frac{α _{1} + α _{2}}{2}$ .

A massless box contains ideal gas moving at 3v. If suddenly stopped, rise in tem

What is thermal coefficient of volume expansion for an ideal gas at constant pre

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