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Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be : [Take specific heat of water = 1 cal−1°C−1 and latent heat of steam = 540 cal−1]
A
24 g
B
31.5 g
C
42.5 g
D
22.5 g
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