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-- Question text hereA particle of mass 5M at rest, disintegrates into two particles of mass 2M and 3M respectively having non-zero velocities. The ratio of de-Broglie wavelength of particle of mass 2M to that of 3M will be
A
2 : 3
B
4 : 9
C
1 : 1
D
3 : 5
Explanation
By conservation of momentum, |p1| = |p2|. Since de-Broglie wavelength λ = h/p, and both particles have equal momentum magnitudes, the ratio of their wavelengths is 1:1.
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