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-- Question text hereThe kinetic energy of the electron orbiting in the first excited state of hydrogen is 3.4 eV. The de-Broglie wavelength associated with the electron is
A
3.31 Å
B
6.63 Å
C
5.46 Å
D
2.84 Å
Explanation
Using λ = h/√(2mK). For K = 3.4 eV, converting to Joules and substituting electron mass, we get approx 6.63 Å. Alternatively, for n=2, 2πr = nλ, where r = 0.529 * n² Å.
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