The figure shows a liquid of given density flowing steadily in horizontal tube of varying cross – section. Cross sectional areas at A is 1.5 cm2 , and B 25 mm2 is , if the speed of liquid at B is 60 cm/s then (PA - PB) is:
(Given PA and PB are liquid pressures at A and B points)
Density = 1000 k gm-3
A and B are on the axis of tube
By equation of continuity,
A1 v1 = A2 v2
(1.5 × 10−4)vA =(25 × 10−6) 60 cm /s
vA = 10 cm /s
By Bernoulli’s theorem,
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