Area of liquid film is 6×10 cm2 and surface tension is T = 20 dyne/cm, what is the work done to change area up to 12 × 10 cm2 :
Initial area = 6x10 cm2
final area = 12x10 cm2
Surface tension (T) = 20 dyne/cm
Work done = change in area x surface tension
= (120-60) x 20
= 1200 erg
Since the film is considered double layered.
∴ Total work done= 2x1200 = 2400 erg
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