What is the mass of oxygen required for the complete combustion of 2.8 kg of ethylene?
C2H4 + 3O2 → 2CO2 + 2H2O
Reaction:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
Given:
Mass of C₂H₄ = 2.8 kg = 2800 g
Moles of C₂H₄ = 2800/28 = 100 mol
From reaction,
1 mol C₂H₄ ⟶ 3 mol O₂
100 mol C₂H₄ ⟶ 300 mol O₂
Mass of O₂ = 300 × 32
= 9600 g
= 9.6 kg
∴ Mass of O₂ required = 9.6 kg
The number of significant figures for the three measurements 161 cm, 0.161 cm, 0
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