The moles of O2 required for reacting with 6.8 g of ammonia is:
4NH3 + 5O2 → 4NO + 6H2O
4NH3 + 5O2 → 4NO + 6H2O
5 moles of oxygen required to react with 4 mole of ammonia.
Thus ‘x’ mole of oxygen will react with 6.8/17 mole of ammonia.
x = = 0.5
Hence, the number moles of O2 required is 0.5 mol.
The mass of 1 × 1023 molecules of H2O is:
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