Consider a particle moving along a straight line, whose position as a function of time is given by s(t) = αt² − βt + γ, where α = 1 ms⁻², β = 6 ms⁻¹ and γ = 5 m. The average speed of the particle, in

Question

Consider a particle moving along a straight line, whose position as a function of time is given by s(t) = αt² − βt + γ, where α = 1 ms⁻², β = 6 ms⁻¹ and γ = 5 m. The average speed of the particle, in ms⁻¹, from t = 0 to t = 6 s is :

Accepted Answer

Answer: 3 — S = αt² − βt + γ S = t² − 6t + 5 ∴ v = ds/dt = (2t − 6) m/s distance travelled = |A₁| + |A₂| distance = 2[1/2 × 3 × 6] distance = 18 m ∴ Average speed ⇒ Vavg = distance/Time Vavg = 18/6 = 3 m/s

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