EasyRe-NEET 2026
+4 / -1
Consider the reversible processes for 1.0 mol of an ideal gas as shown in the figure. w₁, w₂, w₃ and w₄ represent work done (in calories) in the processes 1, 2, 3 and 4, respectively. ΔU₂ and ΔU₄ are changes in the internal energy for the processes 2 and 4, respectively. (use R = 2 cal K⁻¹ mol⁻¹) The correct option is
A
w₁ + w₃ = −2T₁ ln(V₂/V₁) − 2T₂ ln(V₄/V₃)
B
w₂ + w₄ = ΔU₂ − ΔU₄
C
w₁ + w₂ = 2T₁ ln(V₂/V₁)
D
w₁ + w₂ + w₃ + w₄ = 0
Explanation
Process-1 is Isothermal reversible process w₁ = −nRT ℓn(Vf/Vi) = −1 × 2 × T₁ ℓn(V₂/V₁) = −2T₁ ℓn(V₂/V₁) Process-3 is Isothermal reversible process w₃ = −nRT ℓn(Vf/Vi) = −1 × 2 × T₂ ℓn(V₄/V₃) = −2T₂ ℓn(V₄/V₃) w₁ + w₃ = −2T₁ ℓn(V₂/V₁) − 2T₂ ℓn(V₄/V₃) Process-2 is Reversible adiabatic process (expansion) w₂ = ΔU₂ = nCv ΔT = 1 × Cv(T₂ − T₁) = Cv(T₂ − T₁) Process-4 is Reversible adiabatic process (compression)
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