EasyRe-NEET 2026
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The lanthanide ion having four unpaired electrons is (Given : Atomic number of Ce = 58, Nd = 60, Tb = 65 and Ho = 67)
A
Nd³⁺
B
Ce³⁺
C
Tb³⁺
D
Ho³⁺
Explanation
A) Nd³⁺ ⇒ 4f³ ⇒ n = 3 (B) Ce³⁺ ⇒ 4f¹ ⇒ n = 1 (C) Tb³⁺ ⇒ 4f⁸ ⇒ n = 6 (D) Ho³⁺ ⇒ 4f¹⁰ ⇒ n = 4
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