For an elementary chemical reaction, the Arrhenius plot is given below. If the energy of activation is 6.64 kJ mol⁻¹ and R = 8.3 J K⁻¹ mol⁻¹, the temperature at which the rate constant becomes e² min⁻

Question

For an elementary chemical reaction, the Arrhenius plot is given below. If the energy of activation is 6.64 kJ mol⁻¹ and R = 8.3 J K⁻¹ mol⁻¹, the temperature at which the rate constant becomes e² min⁻¹, is

Accepted Answer

Answer: 200 K — ℓn k = ℓn A − Ea/RT ℓn A = 6 (from graph) k = e², T = ? ℓn e² = 6 − (6.64 × 1000)/(8.3 × T) 2 = 6 − 6640/(8.3 × T) 6640/(8.3 × T) = 4 T = 200 K

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