EasyRe-NEET 2026
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In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with KMnO₄ solution. If the volume of KMnO₄ solution required to reach end point is 10 mL, the strength of the KMnO₄ solution is
A
0.10 M
B
0.20 M
C
0.25 M
D
0.15 M
Explanation
Equivalents of oxalic acid = Equivalents of KMnO₄ Normality × volume = Normality × volume N₁V₁ = N₂V₂ M₁ × vf × V₁ = M₂ × vf × V₂ 0.25 × 2 × 10 = M₂ × 5 × 10 M₂ = 0.10 M
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