A block is dragged on smooth plane with the help of a rope which moves with velocity v. The horizontal velocity of the block is :
v
v /sinθ
v sinθ
v /cosθ
Apply Pythagoras theorem in ABC x + y = ....(1)
Differentiate equation (1) with respect to t = horizontal velocity
2x. dx/dt+ 0 = 2ℓ. dℓ/ dt
dx/dt = horizontal velocity
& dl/dt = v(given)
d(y 2)/ dt = 0, because there is no velocity in y direction
dx/ dt = l/x (v)
from tringle ABC
ℓ/ x = 1/ sinθ
dx/ dt = v /sinθ
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