Two particles are projected at speed 3 m/s and 6 m/s horizontally in the same direction from the top of a tower. If both of them strike the ground at points 12 m apart, then the height of tower will b

Question

Two particles are projected at speed 3 m/s and 6 m/s horizontally in the same direction from the top of a tower. If both of them strike the ground at points 12 m apart, then the height of tower will be [Use g = 10 m/s²]

Accepted Answer

Answer: 80 m — Time of flight for both particles will be same. Let time of flight be ‘T’. Now, 12 = 6T – 3T T = 4 sec Also, T = ⇒ H = 1/2 gT² ∴ H = 1/2 (10)(4)² = 80 m

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