Two quantities are measured as A = 1.0 m ± 0.2 m and B = 2.0 m ± 0.2 m. The correct value of should be reported as
If y = then = [ + ]
Here y = = = 1.414 m
or y = 1.4 m (rounding off to two significant digits)
Now, = 1/2 (0.2/1 + 0.2/2)
Δy = 1/2 (0.2 + 0.1)(1.4)
Δy = 0.21 ≈ 0.2 (rounding off to 1 decimal place)
∴ y = (1.4 ± 0.2) m
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