A packet contains silver powder having mass (20.23 ± 0.01) g. Some additional powder of mass (5.75 ± 0.01) g is added to the packet, the total mass of the powder now is;
(14.48 ± 0.02) g
(25.00 ± 0.02) g
(25.98 ± 0.01) g
(25.98 ± 0.02) g
The mass of powder will be the sum of mass of initial powder and extra added powder.
= (20.23 ± 0.01) g + (5.75 ± 0.01) g
= (25.98 ± 0.02) g
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