Write the dimensions of a/b in the relation P = (a - t²) / bx; where P is the pressure, x is the
distance, and t is the time;
[M⁻¹L⁰T⁻²]
[ML⁰T⁻²]
[ML⁰T²]
[MLT⁻²]
Correction option is (2)
P = (a − t²) / bx
P = [ML⁻¹T⁻²]
a will have same unit as t². So,
a = [T²]
b = [(a − t²) / Px] = [T²] / [ML⁻¹T⁻² × L] = [M⁻¹L⁰T⁴]
a / b = [T²] / [M⁻¹L⁰T⁴] = [ML⁰T⁻²]
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