HardPhysics
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-- A particle of charge per unit mass α is released from origin with velocity v = v0 i in a magnetic field B = -B0 k. The x-coordinate of the particle at t = π / (2B0α) would be
A
v0 / (B0α)
B
2v0 / (B0α)
C
Zero
D
v0 / B0α
Explanation
The particle moves in a circle in the xy-plane. Radius R = mv / (qB) = v0 / (B0α). The coordinates are x = R sin(ωt) and y = R(1 - cos(ωt)), where ω = B0α. At t = π / (2ω), x = R sin(π/2) = R = v0 / (B0α).
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