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-- Two identical string instruments initially vibrate with a frequency of 200 Hz. If the tension in one of the instruments is increased by 2% and both are sounded simultaneously, then the number of beats produced per second will be
A
4 Hz
B
1 Hz
C
1/2 Hz
D
2 Hz
Explanation
Frequency f ∝ √T. So df/f = 1/2 (dT/T). Given dT/T = 2%, df/f = 1/2 (2%) = 1%. df = 1% of 200 Hz = 2 Hz. The number of beats is the difference in frequency, which is 2 Hz.
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