MediumPhysics
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A block of mass 2 kg is pushed on a rough horizontal surface with momentum 4√10 kg m/s. If block stopped after moving a distance 8 m on the surface, then coefficient of friction between the block and the surface is
A
1.4
B
0.4
C
0.8
D
0.25
Explanation
Initial velocity u = p/m = 4√10 / 2 = 2√10 m/s. Using v^2 = u^2 + 2as: 0 = (2√10)^2 - 2(μg)(8) => 0 = 40 - 16μ(10) => 160μ = 40 => μ = 40/160 = 0.25.
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