HardPhysics
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-- A conducting uniform rod of length l is placed in a uniform magnetic field B (pointing inward). At t = 0, it starts moving with velocity v and rotating with angular velocity ω about its centre as shown in the figure. The value of induced emf between its two ends at this instant will be (c is the centre of the rod)
A
Blv
B
Zero
C
Blv + (Bωl^2)/2
D
Blv + (Bωl^2)/8
Explanation
The induced emf due to translation is Blv. The induced emf due to rotation about the center for the two halves (AC and CB) are equal in magnitude but opposite in direction (opposing each other relative to the ends). Thus, the rotational components cancel out, leaving only the translational emf Blv.
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