EasyPhysics
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-- A wire breaks under a stress of 2 x 10^5 Pa. If the density of the wire is 4 x 10^3 kg/m^3, then the minimum length of the wire which will break under its own weight will be
A
2 m
B
2.5 m
C
1 m
D
5 m
Explanation
Stress = Force / Area = (Mass * g) / Area = (Density * Volume * g) / Area = (Density * Area * L * g) / Area = Density * L * g. So, L = Stress / (Density * g) = (2 x 10^5) / (4 x 10^3 * 10) = 200 / 40 = 5 m.
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