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HardPhysicsfluid
+4 / -1
-- 5. A 2 m wide truck is moving with a uniform speed v₀ = 8 m/s. A pedestrian starts to cross when the truck is 4 m away. The minimum value of v so that he can cross safely is
A
2/√5 m/s
B
8/√5 m/s
C
4/√5 m/s
D
1/√5 m/s

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