Energy released when two deuterons (1H2) fuse to form a helium nucleus (2He4) is : (Given : Binding energy per nucleon of (1H2) : 1.1 MeV and binding energy per nucleon of (2He4) : 7.0 MeV)
Q = (Eb)product − (Eb)reactant
⇒ Q = 4 × 7 − 2[2 × 1. 1] = 28 − 4. 4 eV
⇒ Q = 23. 6 eV
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