For a projectile thrown according to the situation given below; maximum height acquired by the projectile will be

Use equation of trajectory y = x tanθ ()
Substituting the values in aforementioned equation we get
12 = 18 (1 – 18/R)
2/3 = 1 – 18/R ⇒ R = 54 m
R tanθ = 4H
At θ = 45°
54(1) = 4(H)
∴ H = 54/4 = 13.5 m
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