Position vector of a particle moving in x-y plane is given by = 2tî + (3t – 6t²)ĵ. The equation of trajectory of the particle is

Answer: y = x (1 – x) — Using position vector, separate ‘x’ and ‘y’ components and merge them by substituting value of ‘t’. Here, x = 2t and y = 3t – 6t² ∴ y = 3() – 6()² y = 3 – 6 y = [1 – x]

Position vector of a particle moving in x-y plane is given b... — Physics | Mockzy

EasyPhysicsmotion in a plane

+4 / -1

Position vector of a particle moving in x-y plane is given by $r$ = 2tî + (3t – 6t²)ĵ. The equation of trajectory of the particle is

y = $\frac{3}{2}$ x (x + 1)

y = $\frac{3}{2}$ x (1 – x)

y = x $(\frac{3 - x}{2})$

y = 3x – 6x²

A stone is projected at an angle of 45° above the horizontal with speed 10√2 m/s

Which of the following set of magnitude of vectors cannot give zero resultant?

Practice Physics Exams

Full-length mock tests with detailed analytics, rank, and percentile.

Browse Exams