A particle starts from origin at t = 0 with velocity 6ĵ m/s in xy plane with constant acceleration of = (2î – 2ĵ) m/s². Position coordinates of the particle (in m) when velocity becomes parallel to x-axis is
If velocity is parallel to x axis then vy = 0
= + t
= 6ĵ + (2î – 2ĵ)t
for vy = 0, 6 – 2t = 0
∴ t = 3 seconds
Thus x = (2)(3)² = 9 m
and, y = 6(3) – (2)(3)² = 9 m
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