EasyPhysicsvector
+4 / -1
The projection of vector A along vector B is:
A
A cosθ
B
A sinθ
C
A/B
D
AB
Explanation
To find the projection (component) of A along B, use the dot product with unit vector of B: A·B̂ = A cosθ. This gives the scalar component. The vector component = (A cosθ)B̂.
Previous
The definite integral ∫₀² x dx equals:
NextWhich of the following is correct for small angles (θ in radians)?
More from vector
Medium
A vector A of magnitude 10 N makes an angle of 60° with the x-axis. Its x-component is:
Easyî × î equals:
MediumThe angle between vectors A = î + ĵ and B = î - ĵ is:
EasyIf A = 3î + 4ĵ, the magnitude of vector A is:
EasyThe cross product of two vectors A and B inclined at angle θ has magnitude:
EasyFind the derivative of:
Practice Physics Exams
Full-length mock tests with detailed analytics, rank, and percentile.
Browse Exams