A square surface of side L metre is in the plane of the paper. A uniform electric field E (V/m), also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI units associated with the surface is;
As we know, the electric flux (φ) through any surface area is given by, φ = |E. ds| = |E| |ds| cos θ As according to question, surface area is in plane of paper and E is also in plane of paper. So, angle between area vector and E is 90º So, φ = |E| |ds| cos 90º = 0º
A chare q is placed at the centre of the line joining two exactly equal positive
NextGiven below are two statement: one is labelled as Assertion (A) and the other is
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