When photons of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 eV is TB = (TA − 1.50) eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then select incorrect option
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