MediumNEET TEST
+4 / -1
A wire of resistance R is stretched to twice its original length. This stretched wire is then compressed to 1/4 of its new length. What is the final resistance of the wire? (the deformations are uniform)
A
R
B
4R
C
R/4
D
R/16
Explanation
First Step (Stretching): When a wire is stretched to n times its length, resistance becomes n²R. Here n = 2, so new resistance R' = 4R. Second Step (Compression): Now, the wire (with resistance 4R) is compressed to 1/4 of its length. Final resistance = (1/4)² × 4R = R/4.
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