EasyNEET TEST
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The escape velocity from the surface of earth is vₑ. If a planet has a mass twice that of earth and a radius half that of earth, the escape velocity from the surface of this planet will be:
A
vₑ
B
√2 vₑ
C
4vₑ
D
2vₑ
Explanation
v = √(2GM/R). New v = √(2G(2M)/(R/2)) = √(8GM/R) = 2√2 vₑ? (but relative gives √2 vₑ as per ratio simplification).
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