MediumNEET 2025 Paper
+4 / -1
Consider the following compounds: KO₂, H₂O₂ and H₂SO₄ The oxidation states of the underlined elements in them are, respectively,
A
+1, −1, +6
B
+2, −2, +6
C
+1, −2, +4
D
+4, −4, +6
Explanation
KO₂ me O = −1/2 (superoxide → K +1), H₂O₂ me O = −1, H₂SO₄ me S = +6.
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