MediumMathematics
+4 / -1
In a town of 10,000 families, it was found that 40% family buy newspaper A, 20% buy newspaper B and 10% families buy newspaper C, 5% families buy A and B, 3% families buy B and C and 4% buy A and C. If 2% families buy all 3 newspapers, then find the number of families which buy newspaper B only.
A
1200
B
2000
C
1400
D
1800
Explanation
n(only B) = n(B) – n(B∩A) – n(B∩C) + n(A∩B∩C) = 2000 – 500 – 300 + 200 = 1400.
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