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$26 (\frac{2 ^{3}}{3} (2 13) + \frac{2 ^{5}}{5} (4 12) + \frac{2 ^{7}}{7} (6 12) + \dots + \frac{2 ^{13}}{13} (12 12)) = 3^{13} - α,$

then \alpha is equal to:

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