Given below are two statements :
Statement-I : Due to increase in van der Waals forces, the order of boiling points is CH₃CH₂CH₂I > CH₃CH₂I > CH₃I.
Statement-II : As p-dichlorobenzene is more symmetric, its melting point is higher than o-dichlorobenzene, however its boiling point is lower than o-dichlorobenzene. In the light of the above statements, choose the correct answer from the options given below :
Statement-I is true because van der Waals forces increase with molecular size, so boiling point increases as: CH₃CH₂CH₂I > CH₃CH₂I > CH₃I.
Statement-II is true because p-dichlorobenzene is more symmetrical, giving better crystal packing and hence a higher melting point than o-dichlorobenzene. However, due to lower net dipole moment, its boiling point is lower than o-dichlorobenzene.
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