Heat of reaction for
C6H12O6 (s) + 6O2(g) →6CO2 (g) + 6H2O (g)
at constant pressure is –651 Kcal at 17ºC. Calculate the heat of reaction at constant volume at 17ºC-
-554.5 Kcal
-654.5 Kcal
-354.5 Kcal
-154.5 Kcal
H = ∆E + ∆n RT
Given
∆H = – 651 x 103 cal. , R = 2 cal,
T = 290 K and ∆n = 6 + 6 – 6 = 6
∆E = – 651 × 103 – 6 × 2 × 290
= – 654480 cal
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