What amount of sodium propanoate should be added to one litre of an aqueous solution containing 0.02 mole of propanoic acid (Ka = 1.0 × 10–5 at 25ºC) to obtain a buffer solution of pH 6
0.1 M
0.2 M
0.3 M
0.4 M
Using the expression
pH = pKa + log
we get, 6 = –log(1.0 ×10–5) + log
Which gives 6 = 5 + log
or = 10 or [Salt] = 0.2 M
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