MediumChemistry1
+4 / -1
Heat of reaction for C6H12O6 (s) + 6O2 (g) -> 6CO2 (g) + 6H2O (g) at constant pressure is –651 Kcal at 17ºC. Calculate the heat of reaction at constant volume at 17ºC-
A
– 554.5 Kcal
B
– 654.5 Kcal
C
– 354.5 Kcal
D
– 154.5 Kcal
Explanation
delta H = delta E + delta n RT. Given delta H = – 651 x 103 cal., R = 2 cal, T = 290 K and delta n = 6 + 6 – 6 = 6. delta E = – 651 × 103 – 6 × 2 × 290 = – 654480 cal = – 654.5 Kcal.
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