Heat of reaction for
C6H12O6 (s) + 6O2(g) → 6CO2 (g) + 6H2O (g)
at constant pressure is –651 Kcal at 17ºC. Calculate the heat of reaction at constant volume at 17ºC
– 554.5 Kcal
– 654.5 Kcal
– 354.5 Kcal
– 154.5 Kcal
∆H = ∆E + ∆n RT
Given
DH = – 651 x 103 cal. , R = 2 cal,
T = 290 K and ∆n = 6 + 6 – 6 = 6
\ ∆E = – 651 × 103 – 6 × 2 × 290
= – 654480 cal
= – 654.5 Kcal
A gas absorbs 200J of heat and expands against the external pressure of 1.5 atm
NextIdentify the state functions among the following
Which of the following is correct option for free expansion of an ideal gas under adiabatic conditio
HardUnder the same conditions how many ml of 1 M KOH and 0.5 M H₂SO₄ solutions respectively when mixed f
Hard1 gm H₂ gas at S.T.P. is expanded so that volume is doubled. Hence work done is -
HardThe lattice enthalpy and hydration enthalpy of four compounds are given below – Compound Lattice ent
HardStandard enthalpies of formation of O₃, CO₂, NH₃ and HI are 142.2, −393.2, −46.2 and +25.9 kJ mol⁻¹
HardConsider the following reactions at 1000°C - I. Zn(s) + 1/2 O₂(g) → ZnO(s); ΔG° = −360 kJ mol⁻¹ II.
Practice Chemistry Exams
Full-length mock tests with detailed analytics, rank, and percentile.
Browse Exams