In which of the following reactions H2O2 acts as a reducing agent?
H2O2 + 2H+ + 2e− → 2H2O
H2O2 → O2 + 2H+ + 2e−
H2O2 + 2e− → 2OH−
H2O2 + 2OH− → O2 + 2H2O + 2e−
Given Half Reaction:
H₂O₂ + 2OH⁻ → O₂ + 2H₂O + 2e⁻
Oxidation States:
In H₂O₂:
O = -1
In O₂:
O = 0
Change:
O : -1 → 0
Increase in oxidation number
⇒ Oxidation
Electrons are released (2e⁻)
∴ H₂O₂ acts as a Reducing Agent.
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