6.022 × 1021 molecules of glucose are present in 100 mL of solution. The concentration of solution is:

Answer: 0.1 M — Moles of glucose = = 0.01Molarity of solution = = = 0.1 M

6.022 × 1021 molecules of glucose are present in 100 mL of s... — Chemistry | Mockzy

MediumChemistryConcentration Terms

+4 / -1

0.1 M

0.01 M

1 M

10 M

Find the number of atoms present in 1.6 g of methane:

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