92g of a compound on analysis gave 24g C, 4g H and 64g O. The empirical formula of compound is;

Answer: CH2O2 — Moles of C = 24/12 = 2 Moles of H = 4/1 = 4 Moles of O = 64/16 = 4 Empirical formula = CH2O2

92g of a compound on analysis gave 24g C, 4g H and 64g O. Th... — Chemistry | Mockzy

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