92g of a compound on analysis gave 24g C, 4g H and 64g O. The empirical formula of compound is;
C2H4O2
C2H2O2
CH2O2
CH2O
Moles of C = 24/12 = 2
Moles of H = 4/1 = 4
Moles of O = 64/16 = 4
Empirical formula = CH2O2
4 moles of SO2 and 6 moles of O2 react to form SO3. Total number of moles of rea
NextCalculate the total number of moles in 5.6 L N2.
The simplest formula of the compound containing 50% X (atomic mass 10 amu) and 50% Y (atomic mass 20
EasyThe molecular formula of a compound is C6H12O6. What’s the empirical formula?
MediumEmpirical formula of a hydrocarbon containing 85.71% carbon is:
MediumGiven below are two statements: Statement I: Average atomic mass of chlorine is fractional. Statemen
MediumFor the reaction, when 2 mole of ammonia and 3 mol of oxygen are allowed to react then;
MediumThe flasks of same volume are filled with , and respectively at same temperature and pressure. The w
Practice Chemistry Exams
Full-length mock tests with detailed analytics, rank, and percentile.
Browse Exams