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EasyChemistryChemical Reaction- Alkyl Halide
+4 / -1
An organic compound on treatment with alcoholic KOH gives a hydrocarbon of a molecular formula C₄H₈. Oxidation of the hydrocarbon gives propionic acid and CO₂. The organic compound should be -
A
C₂H₅–CH₂–CH₂Cl
B
CH₃–CH₂–CH(Cl)–CH₃
C
CH₃–CH=C(Cl)–CH₃
D
CH₃–CH(Cl)–CH₂Cl

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