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MediumChemistryEMF of cell
+4 / -1

The reduction potential of the two half cell reactions are

PbSO₄ + 2e⁻ → Pb + SO₄²⁻ E° = –0.31 V

Ag⁺ + e⁻ → Ag E° = +0.80 V The feasible reaction will be-

A
Pb + SO₄²⁻ + 2Ag⁺ → 2Ag + PbSO₄
B
PbSO₄ + 2Ag⁺ → Pb + SO₄²⁻ + 2Ag
C
Pb + SO₄²⁻ + Ag → Ag⁺ + PbSO₄
D
PbSO₄ + Ag → Ag⁺ + Pb + SO₄²⁻

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