Cathode: 2H⁺ + 2e⁻ → H₂
Anode: 2H₂O → O₂ + 4H⁺ + 4e⁻
For same charge: 1 mol H₂ is liberated for every 0.5 mol O₂.
Mass ratio = 2 : 16 = 1 : 8
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